This Ratio and Proportion – CA Foundation Maths Study Material is designed strictly as per the latest syllabus and exam pattern.

## Ratio and Proportion – CA Foundation Maths Study Material

**Ratio:**

The comparison of two or more things of same kind is called Ratio. If x and y are two values of same kind (in same units), then the ratio of x to y is written as x : y and read as x is to y.

In \(\frac{x}{y}\)

- Numerator “x” is called 1st term or Antecedent and
- Denominator “y” is called 2nd term or Consequent.
- Antecedent and Consequent must be of same units
- Ratio has no unit.

Remarks:

- Normally a ratio is expressed in simplest form. As. 10:16 = 5:8.
- The order of the terms in a ratio must be maintained. As 3 : 4 is not same as 4:
- Ratio exists only with quantities having same unit (kind).
- If x > y, then the ratio x : y is called of greater inequality.
- If x < y, then the ratio x : y is called of lesser inequality.
- If x = y, then the ratio a : b is called ratio of Equal Equality.
- Duplicate ratio of a : b is a
^{2}: b^{2} - Triplicate ratio of a : b is a
^{3}: b^{3} - Sub-Duplicate ratio of a : b is √a : √b = a
^{1/2}: b^{1/2} - Sub-Triplicate ratio of a : b is 3√a ; 3√b = a
^{1/3}: b^{1/3}

- Inverse ratio of x : y is y : x.
- Commensurable: If the terms of the ratio are integers, the ratio is called commensurable. As. 3 :2
- Incommensurable : If the terms of the ratio are not integers, the ratio is called Incommensurable.

As √3 : √2 cannot be expressed in terms of integers. So, it is Incom-mensurable.

- Compound/Combined Ratio = Product of all ratios.

**Proportion:**

An equality of two ratios is called Proportion. Four quantities a, b, c, d are said to be in proportion if a : b = c : d.

It is also written as

a : b : : c : d

Here a, b, c, d are called 1st; 2nd; 3rd and 4th term of proportionals respectively a c

If \(\frac{a}{b}=\frac{c}{d}\) ⇒ ad = bc.

Product of extreme terms = Product of middle terms.

This rule is called Cross – Product Rule.

In a: b :: c : d. proportion, unit of a and b should be same and that of c and d should also be same.

As. ₹ 6 : ₹ 8 = 12 toffees : 16 toffees are in proportion.

Let a, b and c are of same kind (in same units). a b

If \(\frac{a}{b}=\frac{b}{c}\) ⇒ a : b : : b : c

i. e. a, b, c are in proportion. ‘

Then, this proportion is called continuous proportion.

Here a is 1st proportion c is called 3rd proportion and b is called mean proportion.

b = \(\sqrt{a c}\) = GM of a & c.

**Properties of Proportion**

1. Cross-Product

If a : b : : c : d.

⇒ \(\frac{a}{b}=\frac{c}{d}\) ∴ ad = be.

2. Invertendo

If a : b : : c : d.; Then its inverse

b : a :: d : c also becomes in proportion.

i.e. If \(\frac{a}{b}=\frac{c}{d}\) Then, \(\frac{b}{a}=\frac{d}{c}\)

3. Componendo

If a : b :: c : d.

Then a + b:b::c + d:d.

Proof \(\frac{a}{b}+1=\frac{c}{d}+1 \Rightarrow \frac{a+b}{b}=\frac{c+d}{d}\)

4. Dividendo

If a : b = c : d.

Then a – b : b = c – d : d.

Proof: \(\frac{a}{b}=\frac{c}{d} \Rightarrow \frac{a}{b}-1=\frac{c}{d}-1\)

or \(\frac{a-b}{b}=\frac{c-d}{d}\)

5. Componendo and Dividendo

If a : b : : c : d. ; Dividing (3) by (4)

Then, \(\frac{a+b}{a-b}=\frac{c+d}{c-d}\)

6. Alternendo:

If a : b : : c : d

Then a : c : : b : d

i.e ratio of alternate terms are also in proportion.

7. Addendo

If a : b = c : d = e : f = …………………

Then each ratio = \(\frac{\text { Sum of antecedents of all ratios }}{\text { Sum of consequents of all ratios }}\)

∴ \(\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\ldots \ldots \ldots .=\frac{a+c+e+\ldots \ldots}{b+d+f+\ldots}\)

8. Subtrahendo

If \(\frac{a}{b}=\frac{c}{d}=\frac{e}{f}\) = ……….

Then each ratio

∴ \(=\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\ldots \ldots \ldots .=\frac{a-c-e-\ldots .}{b-d-f-\ldots .}\)

**Previous Year Exam Questions**

Question 1.

Two numbers are in the ratio of 2 : 3 and the difference of their squares is 320. The number are : [1 Mark, Nov. 2006]

(a) 12, 18

(b) 16, 24

(c) 14, 21

(d) None

Answer:

Tricks : Go by choices (a); (b) & (c) all are in ratio 2:3 But For option

(a) 18^{2} – 12^{2} ≠ 320

(b) 24^{2} – 16^{2} = (24+ 16) (24 – 16)

= 40 × 8 = 320

Question 2.

If p : q is the sub-duplicate ratio of p – x^{2}: q – x^{2}, then x^{2} is : [1 Mark, Nov. 2006]

(a) \(\frac{p}{p+q}\)

(b) \(\frac{q}{p+q}\)

(c) \(\frac{q p}{p-q}\)

(d) None

Answer:

Detail Method:

\(\frac{\sqrt{p-x^2}}{\sqrt{q-x^2}}=\frac{p}{q}\)

Squaring on both side; we get

\(\frac{p-x^2}{q-x^2}=\frac{p^2}{q^2}\)

or pq^{2} – q^{2}x^{2} = p^{2}q – p^{2}x^{2}

or p^{2}x^{2} – q^{2}x^{2} = p^{2}q – pq^{2}

or x^{2}(p^{2} – q^{2}) = pq(p – q)

or x^{2} (p + q)(p-q) = pq (p – q)

(d) is correct

Tricks : Go by choices.

Question 3.

An alloy is to contain copper and zinc in the ratio 9:4. The zinc required to melt with 24 kg of copper is : [1 Mark, Nov. 2006]

(a) 10\(\frac{2}{3}\)kg

(b) 10\(\frac{1}{3}\)kg

(c) 9\(\frac{2}{3}\)kg

(d) 9 kg

Answer:

Let Zinc = x kg

(a) ∴ \(\frac{9}{4}=\frac{24}{x}\) ∴ x = \(\frac{4 \times 24}{9}=\frac{32}{3}\)

= 10\(\frac{2}{3}\)kg

∴ (a) is correct

Question 4.

Two numbers are in the ratio 7: 8. If 3 is added to each of them, their ratio becomes 8 : 9. The numbers are: [1 Mark, Feb. 2007]

(a) 14,16

(b) 24,27

(c) 21,24

(d) 16,18

Answer:

Tricks : Go by choices

(b) and (d) are not in the ratio 7 : 8 So (b) & (d) are not answer For (a) it is added then

\(\frac{14+3}{10+3}=\frac{17}{19} \neq \frac{8}{9}\)

(a) is not answer

(c) is answer Detail Method:

Let x is common in the ratio

∴ Numbers are 7x & 8x

Now \(\frac{7 x+3}{8 x+3}=\frac{8}{9}\)

or 64x + 24 = 63x + 27

or 64x – 63x = 27-24

or x = 3

1st number = ix = 7×3 = 21

2nd number = 8x = 8×3 = 24

(c) is correct

Question 5.

A box contains ₹ 56 in the form of coins of one rupee, 50 paise and 25 paise. The number of 50 paise coin is double the number of 25 paise coins and four times the numbers of one rupee coins. The numbers of 50 paise coins in the box is : [1 Mark, Feb. 2007]

(a) 64

(b) 32

(c) 16

(d) 14

Answer:

Tricks : Go by choices

No. of 25 paise coins = \(\frac{1}{2}\) No. of 50 Paise

No. of Rupee coins = \(\frac{1}{4}\) No. of 50 Paise Coins

For (a) No. of coins of ₹ 1;50 Paise & 25 Paise

\(\frac{64}{4}\); 64; \(\frac{64}{2}\)

Total Value = 16 × 1 + 64 × 0.50 + 32 × 0.25

= ₹ 16 + 32 + 8 = ₹ 56

Which is equal to given value (a) is Correct

Detail Method

Let No. of 50 Paise coins = x

∴ No. of ₹ 1 coins = \(\frac{x}{4}\)

and No. of 25 Paise coins = \(\frac{x}{2}\)

∴ Total Value =

\(\frac{x}{4}\) × 1 + x × 0.50+ \(\frac{x}{2}\) × 0.25 = 56

or 0.25x + 0.50x + 0.125x

or 0.875x = 56

or x = \(\frac{56}{0.875}\) = 64

∴ (a) is correct

Question 6.

Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally entire cost of the car, then the share of each of the remaining persons increased by : [1 Mark, May 2007]

(a) 1/9

(b) 1/8

(c) 1/7

(d) 7/8

Answer:

Tricks : Per Person share increase = \(\frac{1}{7}\) of total share

Question 7.

A bag contains ₹ 187 in the form of 1 rupee, 50 paise and 10 paise coins in the ratio 3:4:5. Find the number of each type of coins: [1 Mark, May 2007]

(a) 102, 136, 170

(b) 136, 102, 170

(c) 170, 102, 136

(d) None

Answer:

Tricks I: Go by choices

For (a) Coins are in the ratio 3:4:5

∴ \(\frac{102}{3}=\frac{136}{4}=\frac{170}{5}\) = 34

It satisfies 1st condition

Now 102 × 1 + 136 × 0.50 + 170 × 0.10

= 102 + 68 + 17 = ₹ 187

∴ (a) is correct

Tricks II

Common factor = \(\frac{187}{3 \times 1+4 \times 0.50+5 \times 0.10}\)

= \(\frac{187}{5.50}\) = 34

∴ No. of 1 Rupee coins =3 × 34 = 102

No. of 50 Paise coins =4 × 34 = 136

No. of 10 paise coins = 5 × 34 = 170 (a) is correct

Detail Method

Let x is common in the ratio

No. of 1 Rupee ; 50 Paise and 10 Paise Coins are 3x ; 4x and 5x

∴ 3x × 1 + 4x × 0.50 + 5x × 0.10 = 187

or 5.50x = 187

∴ x = \(\frac{187}{5.50}\) = 34

∴ No. of 1 Rupee coins = 3x = 3 × 34 = 102

No. of 50 Paise coins = 4x = 4 × 34 = 136

No. of 10 Paise coins = 5x = 5 × 34 = 170

∴ (a) is correct

Question 8.

Ratio of earnings of A and B is 4 : 7. If the earnings of A increase by 50% and those of B decrease by 25%, the new ratio of their earning becomes 8 : 7. What is A’s earning ?

(a) ₹ 21,000

(b) ₹ 26,000

(c) ₹ 28,000

(d) Data inadequate [1 Mark, Aug. 2007]

Answer:

Detailed Method Let x is common in the ratio

∴ A’s and B’s present earnings are 4x and 7x respectively

From question \(\frac{4 x+4 x \times 0.50}{7 x-7 x \times 0.25}=\frac{8}{7}\)

or \(\frac{6 x}{5.25 x}=\frac{8}{7}\)

x cannot be found.

Data is inadequate

∴ (d) is Correct

Question 9.

P, Q and R are three cities. The ratio of average temperature between P and Q is 11 : 12 and that of between P and R is 9: 8. The ratio between the average temperature of Q and R is : [1 Mark, Aug. 2007]

(a) 22: 27

(b) 27: 22

(c) 32: 33

(d) None

Answer:

∴ P: Q= 11 : 12 ∴ Q :P= 12 : 11

\(\frac{Q}{P} \times \frac{P}{R}=\frac{12}{11} \times \frac{9}{8}\)

\(\frac{Q}{R}=\frac{27}{22}\) Q :P= 12 : 11

(b) is Correct

Question 10.

₹ 407 are to be divided among A, B and C so that their shares are in the ratio \(\frac{1}{4}: \frac{1}{5}: \frac{1}{6}\)

The respective shares of A, B, C are: [1 Mark, Nov. 2007]

(a) ₹ 165, ₹ 132, ₹ 110

(b) ₹ 165, ₹ 110, ₹ 132

(c) ₹ 132, ₹ 110, ₹ 165

(d) ₹ 110, ₹ 132, ₹ 165.

Answer:

A:B:C = \(\frac{1}{4}: \frac{1}{5}: \frac{1}{6}\) × LCM of denominators = 60

= 15 : 12 : 10

∴ A’s share = \(\frac{407}{15+12+10}\) × 15 = Rs. 165

B’s share = \(\frac{407}{37}\) × 12 = Rs. 132

C’s share = \(\frac{407}{37}\)× 10 = Rs. 110

(a) is Correct

Tricks : Go by Choices.

Question 11.

The incomes of A and B are in the ratio 3 :2 and their expenditures in the ratio 5 : 3. If each saves ₹ 1,500, then B’s income is : [1 Mark, Nov. 2007]

(a) ₹ 6,000

(b) ₹ 4,500

(c) ₹ 3,000

(d) ₹ 7,500

Answer:

Detail Method Let x is common in the ratio.

A’s income = 3x

B’s income = 2x

∴ \(\frac{3 x-1500}{2 x-1500}=\frac{5}{3}\)

or 10x – 7500 = 9x – 4500

or 10x – 9x = 7500 – 4500

or x = 3000

B’s income = 2x =2 × 3000

= ₹ 6000.

(a) is Correct Tricks : Go by choices For (a)

\(\frac{A}{B}\) Expenditure = \(\frac{\frac{6000}{2} \times 3-1500}{6000-1500}=\frac{7500}{4500}=\frac{5}{3}\)

(a) is Correct

Question 12.

In 40 litres mixture of glycerine and water, the ratio of glycerine and water is 3:1. The quantity of water added in the mixture in order to make this ratio 2:1 is : [1 Mark, Feb. 2008 ]

(a) 15 litres

(b) 10 litres

(c) 8 litres

(d) 5 litres

Answer:

Glycerine = \(\frac{40}{3+1}\) x 3 = 30 litres.

Water = \(\frac{40}{4}\) x 1 = 10 litres 4

Let x litres of water is added to the mixture

Then \(\frac{30}{10+x}=\frac{2}{1}\)

or, 2x + 20 = 30

or x = 5

∴ (d) is Correct

Tricks : Go by Choices

Question 13.

The third proportional between (a^{2} – b^{2}) and (a + b)^{2} is : [1 Mark, Feb. 2008]

(a) \(\frac{a+b}{a-b}\)

(b) \(\frac{a-b}{a+b}\)

(c) \(\frac{(a-b)^2}{a+b}\)

(d) \(\frac{(a+b)^3}{a-b}\)

Answer:

3rd Proportion = \(\frac{(\text { Mean prop. })^2}{\text { lst Proportional }}\)

= \(\frac{\left\{(a+b)^2\right\}^2}{a^2-b^2}=\frac{(a+b)^4}{3(a+b)(a+b)}=\frac{(a+b)^3}{a-b}\)

(d) is Correct

Question 14.

In what ratio should tea worth ₹ 10 per kg. be mixed with tea worth ₹ 14 per kg., so that the average price of the mixture may be ₹ 11 per kg.? [1 Mark, June 2008]

(a) 2 : 1

(b) 3 : 1

(c) 3 : 2

(d) 4 : 3

Answer:

∴ (b) is Correct

Question 15.

The ages of two persons are in the ratio 5:7. Eighteen years ago their ages were in the ratio of 8:13, their present ages (in years) are : [1 Mark, June 2008]

(a) 50; 70

(b) 70,50

(c) 40,56

(d) None

Answer:

Tricks : Go by choices (a) & (c) are in the ratio 5 : 7 not (b)

For (a) 18 year ago

So, (a) is Correct

Question 16.

If A, B and C started a business by investing ₹ 1,26,000, ₹ 84,000 and ₹ 2,10,000. If at the end of the year profit is ₹ 2,42,000 then the share of each is : [1 Mark, Dec. 2008]

(a) ₹ 72,600; ₹ 48,400 ; ₹ 1,21,000

(b) ₹ 48,400 ; ₹ 1,21,000 ; ₹ 72,600

(c) ₹ 72,000 ; ₹ 49,000 ; ₹ 1,21,000

(d) ₹ 48,000 ; ₹ 1,21,400 ; ₹ 72,600

Answer:

Investment ratio is

A : B : C = 126,000 : 84,000 : 2,10,000 ÷ 14,000

= 9: 6 : 15 ÷ 3

= 3: 2: 5

A’s share = \(\frac{₹ 242,000}{3+2+5}\) × 3 =₹ 72, 600

B’s share = \(\frac{242,000}{20}\) × 2 = ₹48, 400

C’s share = \(\frac{242000}{10}\) × 5 = ₹ 1,21,000

So, (a) is Correct

Question 17.

If \(\frac{p}{q}=-\frac{2}{3}\) then the value of \(\frac{2 p+q}{2 p-q}\) is: [1 Mark, June 2009]

(a) 1

(b) \(-\frac{1}{7}\)

(c) \(\frac{1}{7}\)

(d) 7

Answer:

∵ \(\frac{p}{q}=\frac{-2}{3}\)

Tricks

\(\frac{2 p+q}{20-q}=\frac{2(-2)+3}{2(-2)-3}=\frac{-4+3}{-4-3}=\frac{-1}{-7}=\frac{1}{7}\)

(c) is correct

Question 18.

Fourth proportional to x, 2x, (x +1) is :

(a) x + 2

(b) (x + 2)

(c) (2x + 2)

(d) (2x – 2)

Answer:

Let Fourth Proportional is K.

∴ \(\frac{x}{2 x}=\frac{x+1}{K}\)

or k.x = 2x (x + 1)

or k = 2 (x + 1) = 2x +2

(c) is correct

Question 19.

What must be added to each term of the ratio 49 : 68 so that it becomes 3 : 4? [1 Mark, June 2010]

(a) 3

(b) 5

(c) 8

(d) 9

Answer:

Detail Method:

Let x is added to each term

Then \(\frac{49+x}{68+x}=\frac{3}{4}\)

or 196 +4x = 204 + 3x

or 4x – 3x = 204 – 196

or x = 8

(c) is Correct

Tricks : Go by Choices

1st Find \(\frac{3}{4}\) = 0.75 (By Calculator)

Question 20.

The students of two classes are in the ratios 5 : 7, if 10 students left from each class, the remaining students are in the ratio of 4 : 6, then the number of students in each class was : [1 Mark, June 2010]

(a) 30, 40

(b) 25, 24

(c) 40, 60

(d) 50, 70

Answer:

Tricks : Go by choices:

(a); (b) and (c) are not in the ratio 5 : 7

∴ (d) is Correct.

Question 21.

If A: B= 2: 5, then (10A + 3B) : (5A + 2B) is equal to: [1 Mark, Dec. 2010]

(a) 7: 4

(b) 7: 3

(c) 6: 5

(d) 7: 9

Answer:

It A : B = 2 : 5 Then

\(\frac{10 A+3 B}{5 A+2 B}=\frac{10 \times 2+3 \times 5}{5 \times 2+2 \times 5}=\frac{35}{20}=\frac{7}{4}\)

= 7: 4

(a) is Correct

Question 22.

In a film shooting, A and B received money in a certain ratio and B and C also received the money in the same ratio. If A gets ₹ 1,60,000 and C gets ₹ 2,50,000. Find the amount received by B ? [1 Mark, June 2011]

(a) ₹ 2,00,000

(b) ₹ 2,50,000

(c) ₹ 1,00,000

(d) ₹ 1,50,000

Answer:

Detail Method

A : B = B : C

So, B^{2} = AC ;

so, B = \(\sqrt{\mathrm{AC}}=\sqrt{1,60,000 \times 2,50,000}\)

= 400 × 500 = 2,00,000

Question 23.

The ratio compounded of 4:5 and sub-duplicate of “ a” : 9 is 8:15. Then value of “a” is: [1 Mark, Dec. 2011]

(a) 2

(b) 3

(c) 4

(d) 5

Answer:

(c) \(\frac{4}{5} \times \sqrt{\frac{a}{9}}=\frac{8}{15}\)

or \(\frac{4}{5} \times \frac{\sqrt{a}}{3}=\frac{8}{15}\)

∴ √a = 2 ⇒ a = 4

(c) is Correct

Question 24.

If X varies inversely as square of Y and given that Y=2 for X = 1, then the value of X for Y =6 will be: [1 Mark, Dec. 2011]

(a) 3

(b) 9

(c) 1/3

(d) 6

Answer:

(d) is Correct

x × \(\frac{1}{y^2}\) ⇒ x = K.\(\frac{1}{y^2}\) x = \(\frac{k}{y^2}\), where k = proportional constant

where k = proportional constant

When x = 1 Then y = 2

1 = \(\frac{k}{2^2}\) ⇒ k = 4 ∴ x = \(\frac{4}{y^2}\)

When y = 6, Then x = \(\frac{4}{6^2}=\frac{1}{9}\)

x = \(\frac{1}{9}\)

Question 25.

Which of the numbers are not in proportion ?

(a) 6, 8, 5, 7

(b) 7, 14, 6, 12

(c) 18, 27,12, 18

(d) 8, 6, 12, 9

Answer:

(a) Go by choices

For (a) \(\frac{6}{8}=\frac{3}{4} \neq \frac{5}{7}\)

(a) is not in proportion

Question 26.

Find two numbers such that mean proportional between them is 18 and third proportional between them is 144: [1 Mark, Dec. 2012]

(a) 9 ; 36

(b) 8 ; 32

(c) 7 ; 28

(d) 6 ; 14

Answer:

(a) is correct Tricks : Go by choices

For (a) Mean Proportional of 9 and 36

= \(\sqrt{9 \times 36}\) = 18

It satisfies 1st condition.

If 144 is its 3rd condition.

36^{2} = 9 × 144

It also satisfies the 2nd Condition.

Question 27.

Triplicate ratio of 4 : 5 is: [1 Mark, June 2013]

(a) 125 : 64

(b) 16 : 25

(c) 64 : 125

(d) 120 : 46

Answer:

(c) Triplicate ratio of 4:5 = 4^{3} :5^{3} = 64: 125

Question 28.

The mean proportion between 24 and 54 is _______. [1 Mark, June 2013]

(a) 33

(b) 34

(c) 35

(d) 36

Answer:

(d) Mean – Proportion = \(\sqrt{24 \times 54}\) = 36

Question 29.

The ratio of numbers is 1:2:3 and sum of their squares is 504 then the numbers are: [1 Mark, Dec. 2013]

(a) 6, 12, 18

(b) 3, 6, 9

(c) 4, 8, 12

(d) 5, 10, 15

Answer:

(a) is correct

Tricks : Go by choices

Tricks : See Quicker BMLRS

Question 30.

If P is 25% less than Q and R is 20% higher than Q the Ratio of R and P: [1 Mark, Dec. 2013]

(a) 5:8

(b) 8:5

(c) 5:3

(d) 3:5

Answer:

(b) is correct

Let Q = 100, So, P = 100 – 025 = 75

&R = 100 + 20= 120

\(\frac{R}{P}=\frac{120}{75}=\frac{8}{5}\)

Question 31.

A person has assets worth ₹ 1,48,200. He wish to divide it amongst his wife, son and daughter in the ratio 3:2:1 respectively. From this assets the share of his son will be: [1 Mark, June 2014]

(a) ₹ 74,100

(b) ₹ 37,050

(c) ₹ 49,400

(d) ₹ 24, 700

Answer:

(c) is correct

Share of son = \(\frac{2}{3+2+1}\) × 1,48,200

= ₹ 49,400

Question 32.

If x : y = 2 : 3 then (5x+2y): (3x -y) = [1 Mark, June 2014]

(a) 19 : 3

(b) 16: 3

(c) 7 : 2

(d) 7: 3

Answer:

(b) is correct

\(\frac{5 x+2 y}{3 x-y}=\frac{5 \times 2+2 \times 3}{3 \times 2-3}=\frac{16}{3}\)

Question 33.

The first, second and third month salaries of aperson are in the ratio 2:4:5. The difference between the product of the salaries of first 2 months & last 2 months is ₹ 4,80,00,000. Find the salary of the second month [1 Mark, Dec. 2014]

(a) ₹ 4,000

(b) ₹ 6,000

(c) ₹ 12,000

(d) ₹ 8,000

Answer:

(d) is correct

Let x is common in the ratio.

1st, 2nd and 3rd month salaries of a person = 2x ; 4x ; 5x

From Qts.

4x × 5x – 2x × 4x = 4,80,00,000.

or, 12x^{2} = 4,80,00,000.

or, x^{2} = 4000000

x = 2000.

2nd month salary = 4x = 4×2000

= ₹ 8000

Question 34.

(2p^{2} – q^{2}) = 7pq, where p, q are positive then p : q. [1 Mark, June 2015]

(a) 5:6

(b) 5:7

(c) 3:5

(d) 3:7

Answer:

(a) is correct 15(2p^{2} – q^{2}) = 7pq

Tricks : Go by choices

For (a) put p = 5; q = 6 we get

15[2 × 5^{2} – 6^{2}] = 3 × 5 × 6

or 15 × 14 = 210

or 210 = 210

Question 35.

If one type of rice of cost ₹ 13.84 is mixed with another type of rice of cost ₹ 15.54, the mixture is sold at ₹ 17.60 with a profit of 14.6% on selling price then in which proportion the two types of rice mixed ? [1 Mark, June 2015]

(a) 3:7

(b) 5:7

(c) 7:9

(d) 9:1

Answer:

Cost of mixture per kg = 17.60 – 14.6% = 15.0304 = 15.03 (approx.)

By rules of Alligation

51: 119 = 3: 7

Go by choices

(a) is correct (approx)

Question 36.

Find the ratio of third proportional of 12 ; 30 and mean proportional of 9; 25 : [1 Mark, Dec. 2015]

(a) 7: 2

(b) 5 : 1

(c) 9 : 4

(d) None of these

Answer:

3rd proportional = \(\frac{30^2}{12}\) = 75

Mean Proportional = \(\sqrt{9 \times 25}\) =15

Ratio = \(\frac{75}{15}\) = 5:1

(b) is correct

Question 37.

What must be added to each of the numbers 10, 18, 22, 38 to make them proportional: [1 Mark, Dec. 2015]

(a) 5

(b) 2

(c) 3

(d) 9

Answer:

(b) is correct

let x be added.

∴ \(\frac{10+x}{18+x}=\frac{22+x}{38+x}\)

Tricks: Go by choices.

∴ x = 2 satisfies it.

Question 38.

x, y, z together starts a business, if x invests 3 times as much as y invests and y invests two third of what z invests, then the ratio of capitals of x, y, z is: [1 Mark, June 2016]

(a) 3 : 9 : 2

(b) 6: 3: 2

(c) 3 : 6 : 2

(d) 6: 2: 3

Answer:(d)

Tricks: Go by choices

6 = 3 × 2 and 2 = 3 × \(\frac{2}{3}\)

Question 39.

A bag contains 23 number of coins in the form of 1 rupee, 2 rupee and 5 rupee coins. The total sum of the coins is ?₹ 43. The ratio between 1 rupee and 2 rupees coins is 3 : 2. Then the number of 1 rupee coins is: [1 Mark, Dec. 2016]

(a) 12

(b) 8

(c) 10

(d) 16

Answer:

(a)

Tricks : Go by choices

Let option (a) is correct.

Let x is common in the ratio.

So, ₹ 1 coins = 3x = 12 ; So, x = 4

No. of ₹ 2 coins = 2 × 4 = 8

Hence no. of coins of ₹ 5 coins = 23 – 12 – 8= 3

Total money = 12 × 1 + 8 × 2 + 3 × 5 = ₹ 43

Satisfied. So (a) is correct.

Question 40.

If a: b = 2: 3, b : c = 4: 5, c: d = 6: 7 then a : d is: [1 Mark, June 2017]

(a) 24 : 35

(b) 8 : 15

(c) 16 : 35

(d) 7 : 15

Answer:

Option (c) is correct.

Multiply all ratios.

= \(\frac{2}{3} \times \frac{4}{5} \times \frac{6}{7}=\frac{16}{35}\)

Question 41.

The ratio of the number of five rupee coins to number of ten rupee coins is 8: 15. If the total value of five rupee coins is 360, then the no. of ten rupee coins is _______. [1 Mark, Dec. 2017]

Answer:

Option (d) is correct.

Total No. of ₹ 5 coins = 360/5 = 72

Let x is common in the ratio.

So, ₹ 5 coins = 8x = 72 ; So, x = 9

No. of ₹ 10 coins = 15 × 9 = 135

Question 42.

If \(\frac{1}{2}, \frac{1}{3}, \frac{1}{5}, \frac{1}{x}\) are in proportion then x = . [1 Mark, Dec. 2017]

(a) \(\frac{15}{2}\)

(b) \(\frac{3}{15}\)

(c) \(\frac{2}{15}\)

(d) \(\frac{1}{15}\)

Answer:

Option (a) is correct.

Product of middle two terms = Product of extremes

So, \(\frac{1}{2 x}=\frac{1}{15}\); x = 15/2

Question 43.

If (a + b): (b + c): (c + a) = 7 : 8 : 9 and a + b + c = 18 then a : b : c = . [1 Mark, June 2018]

(a) 5 : 4 : 3

(b) 3 : 4 : 5

(c) 4 : 3 : 5

(d) 4: 5 : 3

Answer:

(c) 4 : 3 : 5 is correct

Tricks: Go by choices.

(c) Let a : b : c = 4 : 3 : 5

It is in ratio. So, it should must satisfy given ratio (a + b): (b + c): (c + a) = 7 : 8 : 9

i.e. (4 + 3): (3 + 5): (5 + 4) = 7 : 8 : 9 (True) Avoid 2nd condition.

In detail it will take too much time.

Question 44.

If p : q is the sub-duplicate ratio of p – x^{2}:q – x^{2}, then x^{2} is : [1 Mark, May 2018]

(a) \(\frac{p}{p+q}\)

(b) \(\frac{q}{p+q}\)

(c) \(\frac{q p}{p-q}\)

(d) None

Answer:

Question 45.

The mean proportional between 24 and 54 is : [1 Mark, May 2018]

(a) 33

(b) 34

(c) 35

(d) 36

Solution:

Formula

Mean Proportion of a & b = \(\sqrt{a b}\)

(d) = \(\sqrt{24 \times 54}\) = 36

Question 46.

\(\frac{3 x-2}{5 x+6}\) is the duplicate ratio of \(\frac{2}{3}\) then find the value of x : [1 Mark, Nov. 2018]

(a) 6

(b) 2

(c) 5

(d) 9

Answer:

(a)

Given \(\frac{3 x-2}{5 x+6}=\left(\frac{2}{3}\right)^2=\frac{4}{9}\)

Tricks : Go by choices

for option (a) putting x = 6 in LHS; we get

\(\frac{3 \times 2-2}{5 \times 2+6}=\frac{4}{9}\)

∴ (a) is correct.

Question 47.

If x : y : z = 7 : 4 : 11 then is: [1 Mark, Nov. 2018]

(a) 2

(b) 3

(c) 4

(d) 5

Answer:

(a)

\(\frac{x+y+z}{z}=\frac{7+4+11}{11}\) = 2

Question 48.

If the ratio of two numbers is 7 : 11. If 7 is added to each number then the new ratio will be 2 : 3 then the numbers are. [1 Mark, June 2019 ]

(a) 49,77

(b) 42,45

(c) 43,42

(d) 39,40

Answer:

Tricks:- GBC (Go by Choices)

(a)

49 ÷ 7 = 7

77 ÷ 11 = 7 both must be equal.

Here it is correct.

Now:

\(\frac{49+7}{77+7}=\frac{56}{84}=\frac{2}{3}\)

Divide 56 by numerator (2) and 84 by Denominator (3) we get same value “28”

Note:- No need to solve ; only check.

By Calculator.